3x^2+140x-9600=0

Solution for 3x^2+140x-9600=0 equation:

3x^2+140x-9600=0

a = 3; b = 140; c = -9600;
Δ = b2-4ac
Δ = 1402-4·3·(-9600)
Δ = 134800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{134800}=\sqrt{400*337}=\sqrt{400}*\sqrt{337}=20\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-20\sqrt{337}}{2*3}=\frac{-140-20\sqrt{337}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+20\sqrt{337}}{2*3}=\frac{-140+20\sqrt{337}}{6}
$